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A071627
Terms of Chernoff sequence A006939 divided by (n + 1)!.
0
1, 1, 2, 15, 630, 242550, 1040539500, 66400727518125, 71562941411142431250, 1596518198505361496634018750, 938998452767448490315979899506187500, 15693832493195927010608457268015759163973281250
OFFSET
0,3
COMMENTS
I.e. divided by the number of divisors of A006939(n), which is (n + 1)!.
FORMULA
a(n) = A006939(n)/(n + 1)! = A006939(n)/A000005(A006939(n)).
PROG
(PARI) a(n) = prod(k=1, n, prime(k)^(n-k+1))/(n + 1)!; \\ Michel Marcus, Jan 11 2023
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Labos Elemer, May 30 2002
EXTENSIONS
Corrected by Georg Fischer, Jan 11 2023
STATUS
approved