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 A071532 (-1) * Sum[ k =1,n, (-1)^floor((3/2)^k) ]. 4
 1, 0, 1, 2, 3, 4, 5, 6, 5, 6, 5, 6, 5, 6, 7, 6, 7, 8, 7, 8, 9, 10, 9, 8, 9, 8, 9, 8, 7, 8, 7, 8, 9, 10, 11, 10, 9, 10, 9, 8, 7, 8, 7, 6, 7, 8, 7, 8, 7, 6, 5, 6, 7, 6, 7, 6, 7, 8, 9, 8, 9, 10, 11, 12, 13, 12, 11, 10, 11, 10, 11, 10, 9, 10, 9, 10, 9, 8, 7, 6, 5, 6, 7, 6, 7, 6, 5, 4, 5, 6, 5, 4, 5, 4, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,4 COMMENTS Let b(n) denote the number of k with 0<=k<=n such that floor((3/2)^k) = A002379(k) is even; then a(n) = n-2*b(n). Equivalently: let c(n) denote the number of k, 0<=k<=n, such that floor((3/2)^k) = A002379(k) is odd, then a(n) = 2*c(n)-n. Is a(n)>0? For n large enough does a(n)>sqrt(n) always hold? Conjecture: asymptotically, a(n) ~ C * Log(n)^2 with C = 1.4..... LINKS Robert G. Wilson v, Graph of first 100000 terms FORMULA a(n) = (-1)*sum( i=1, n, (-1)^A002379 (i) ) MATHEMATICA a[0] = 0; a[n_] := a[n] = a[n - 1] - (-1)^Floor[(3/2)^n]; Table[ a[n], {n, 0, 95}] PROG (PARI) a(n)=-sum(i=1, n, sign((-1)^floor((3/2)^i))) (PARI) a(n)=n-2*sum(k=0, n, if(floor((3/2)^k)%2, 0, 1)) CROSSREFS Cf. A072418. Sequence in context: A017861 A094700 A073635 * A102730 A165597 A099033 Adjacent sequences:  A071529 A071530 A071531 * A071533 A071534 A071535 KEYWORD easy,nonn AUTHOR Benoit Cloitre, Jun 20 2002 EXTENSIONS Edited by Ralf Stephan, Sep 01 2004 STATUS approved

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