|
%I #13 Jul 16 2021 01:35:27
%S 1,2,5,7,10,14,16,20,24,29,39,40,42,44,46,55,57,59,66,68,70,81,86,91,
%T 106,108,109,117,118,119,120,123,124,133,142,147,155,159,163,164,167,
%U 168,171,176,177,198,201,205,206,213,217,226,227,228,229,233,238,246
%N Numbers k such that the number of terms in the continued fraction for (1 + 1/x)^x equals k for some x.
%C It appears that lim_{n -> infinity} a(n)/(n*log(n)) = 1. - _Benoit Cloitre_, Jan 29 2006
%o (PARI) for(n=1,300,if(sum(i=1,n,if(length(contfrac((1+1/i)^i))-n,0,1))>0,print1(n,",")))
%K easy,nonn
%O 1,2
%A _Benoit Cloitre_, May 27 2002
|
