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A071094
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Number of ways to tile hexagon of edges n, n, n+1, n, n, n+1 with diamonds of side 1.
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2
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1, 3, 50, 4116, 1646568, 3184461423, 29706808370096, 1335119245893326400, 288882990167192721013376, 300792059519113653077154558000, 1506680146887473588202049621593937500, 36298820709557430183399305000196605531250000, 4205446372314569673006362329181090368935937500000000, 2342761095072644391194625697884219372917666852341417500000000
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OFFSET
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0,2
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REFERENCES
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J. Propp, Enumeration of matchings: problems and progress, pp. 255-291 in L. J. Billera et al., eds, New Perspectives in Algebraic Combinatorics, Cambridge, 1999 (see page 261).
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LINKS
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FORMULA
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a(n) = Product_{i=0..a-1} Product_{j=0..b-1} Product_{k=0..c-1} (i+j+k+2)/(i+j+k+1) with a=b=n, c=n+1.
a(n) = Product_{k=0..n} C(2n+k,n+k)/C(n+k,k). - Paul Barry, May 13 2008
a(n) ~ exp(1/12) * 3^(9*n^2/2 + 3*n + 5/12) / (A * n^(1/12) * 2^(6*n^2 + 4*n + 3/4)), where A = A074962 = 1.2824271291... is the Glaisher-Kinkelin constant. - Vaclav Kotesovec, Apr 26 2015
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MATHEMATICA
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Table[Product[(i+j+k+2)/(i+j+k+1), {i, 0, n-1}, {j, 0, n-1}, {k, 0, n}], {n, 0, 15}] (* Vaclav Kotesovec, Apr 26 2015 *)
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PROG
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(PARI) a(n) = prod(k=0, n, binomial(2*n+k, n+k)/binomial(n+k, k)) \\ Michel Marcus, May 20 2013
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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