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a(n) = n^6 mod 19.
0

%I #15 Feb 09 2025 10:56:56

%S 0,1,7,7,11,7,11,1,1,11,11,1,1,11,7,11,7,7,1,0,1,7,7,11,7,11,1,1,11,

%T 11,1,1,11,7,11,7,7,1,0,1,7,7,11,7,11,1,1,11,11,1,1,11,7,11,7,7,1,0,1,

%U 7,7,11,7,11,1,1,11,11,1,1,11,7,11,7,7,1,0,1,7,7,11,7,11,1,1,11,11,1,1,11

%N a(n) = n^6 mod 19.

%H <a href="/index/Rec#order_19">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%F a(n) = a(n-19). - _Wesley Ivan Hurt_, Dec 26 2023

%t PowerMod[Range[0, 100], 6, 19] (* _Wesley Ivan Hurt_, Dec 26 2023 *)

%t PadRight[{},120,{0,1,7,7,11,7,11,1,1,11,11,1,1,11,7,11,7,7,1}] (* _Harvey P. Dale_, Feb 09 2025 *)

%o (Sage) [power_mod(n,6,19)for n in range(0, 90)] # _Zerinvary Lajos_, Nov 06 2009

%o (PARI) a(n)=n^6%19 \\ _Charles R Greathouse IV_, Apr 06 2016

%K nonn,easy,changed

%O 0,3

%A _N. J. A. Sloane_, May 13 2002