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A070592 Largest prime factor of the n-th Fermat number F(n) = 2^(2^n) + 1. 5

%I #18 Jul 05 2017 21:17:52

%S 3,5,17,257,65537,6700417,67280421310721,5704689200685129054721,

%T 93461639715357977769163558199606896584051237541638188580280321

%N Largest prime factor of the n-th Fermat number F(n) = 2^(2^n) + 1.

%H Eric M. Schmidt, <a href="/A070592/b070592.txt">Table of n, a(n) for n = 0..11</a>

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/FermatNumber.html">Fermat Number</a>

%o (PARI) a(n) = vecmax(factor(2^(2^n) + 1)[,1]); \\ _Michel Marcus_, Jul 05 2017

%Y Cf. A000215, A050922.

%K nonn

%O 0,1

%A _Benoit Cloitre_, May 12 2002

%E Offset changed by _Arkadiusz Wesolowski_, Jul 09 2011

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Last modified April 25 03:15 EDT 2024. Contains 371964 sequences. (Running on oeis4.)