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A070532
a(n) = n^4 mod 14.
1
0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2, 1, 0, 1, 2, 11, 4, 9, 8, 7, 8, 9, 4, 11, 2
OFFSET
0,3
COMMENTS
Equivalently: n^(6*m + 4) mod 14. - G. C. Greubel, Apr 01 2016
LINKS
Index entries for linear recurrences with constant coefficients, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
FORMULA
From G. C. Greubel, Apr 01 2016: (Start)
a(n+14) = a(n).
a(14*m) = 0.
a(2*n) = 2*A070512(n).
G.f.: (x +2*x^2 +11*x^3 +4*x^4 +9*x^5 +8*x^6 +7*x^7 +8*x^8 +9*x^9 +4*x^10 +11*x^11 +2*x^12 +x^13)/(1 - x^14). (End)
MATHEMATICA
PowerMod[Range[0, 100], 4, 14] (* G. C. Greubel, Apr 01 2016 *)
PROG
(Sage) [power_mod(n, 4, 14)for n in range(0, 97)] # Zerinvary Lajos, Oct 31 2009
(Magma) [Modexp(n, 4, 14): n in [0..100]]; // Vincenzo Librandi, Apr 02 2016
(PARI) a(n)=n^4%14 \\ Charles R Greathouse IV, Apr 06 2016
CROSSREFS
Cf. A070512.
Sequence in context: A070840 A235460 A082264 * A038217 A152985 A257112
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, May 13 2002
STATUS
approved