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A070479
a(n) = n^3 mod 17.
1
0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16, 0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16, 0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16, 0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16, 0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16, 0, 1
OFFSET
0,3
LINKS
Index entries for linear recurrences with constant coefficients, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
FORMULA
From G. C. Greubel, Mar 28 2016: (Start)
a(n) = a(n-17).
G.f.: (-x - 8x^2 - 10x^3 - 13x^4 - 6x^5 - 12x^6 - 3x^7 - 2x^8 - 15x^9 - 14x^10 - 5x^11 - 11x^12 - 4x^13 - 7x^14 - 9x^15 - 16x^16)/(-1 + x^17). (End)
MATHEMATICA
Table[Mod[n^3, 17], {n, 0, 100}] (* Vincenzo Librandi, Jun 19 2014 *)
PowerMod[Range[0, 120], 3, 17] (* or *) PadRight[{}, 120, {0, 1, 8, 10, 13, 6, 12, 3, 2, 15, 14, 5, 11, 4, 7, 9, 16}] (* Harvey P. Dale, Nov 20 2024 *)
PROG
(Sage) [power_mod(n, 3, 17 )for n in range(0, 87)] # Zerinvary Lajos, Oct 29 2009
(Magma) [n^3 mod 17: n in [0..80]]; // Vincenzo Librandi, Jun 19 2014
(PARI) a(n)=n^3%17 \\ Charles R Greathouse IV, Apr 06 2016
CROSSREFS
Cf. A008960.
Sequence in context: A303223 A112549 A112585 * A335172 A356522 A184116
KEYWORD
nonn,easy,changed
AUTHOR
N. J. A. Sloane, May 12 2002
STATUS
approved