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a(n) = 3^n mod 47.
3

%I #20 Dec 18 2023 14:19:28

%S 1,3,9,27,34,8,24,25,28,37,17,4,12,36,14,42,32,2,6,18,7,21,16,1,3,9,

%T 27,34,8,24,25,28,37,17,4,12,36,14,42,32,2,6,18,7,21,16,1,3,9,27,34,8,

%U 24,25,28,37,17,4,12,36,14,42,32,2,6,18,7,21,16,1,3,9,27,34,8,24,25,28,37

%N a(n) = 3^n mod 47.

%H G. C. Greubel, <a href="/A070364/b070364.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_23">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%F a(n) = a(n-23). - _R. J. Mathar_, Apr 20 2010

%t PowerMod[3, Range[0,50], 47] (* or *) Table[Mod[3^n, 47], {n, 0, 100}] (* _G. C. Greubel_, Mar 09 2016 *)

%o (PARI) a(n)=lift(Mod(3,47)^n) \\ _Charles R Greathouse IV_, Mar 22 2016

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_, May 12 2002