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a(n) = n^reverse(n) (ignore leading 0's).
2

%I #12 Aug 15 2023 07:42:28

%S 1,4,27,256,3125,46656,823543,16777216,387420489,10,285311670611,

%T 46005119909369701466112,34059943367449284484947168626829637,

%U 98005277522749794820791054154499091349964324864

%N a(n) = n^reverse(n) (ignore leading 0's).

%H Vincenzo Librandi, <a href="/A070271/b070271.txt">Table of n, a(n) for n = 1..100</a>

%F a(n) = n^A004086(n). - _Michel Marcus_, May 31 2014

%e a(10) = 10^reverse(10) = 10^1 = 10.

%t Table[n^FromDigits[Reverse[IntegerDigits[n]]], {n, 1, 12}]

%Y Cf. A004086, A070834.

%K base,nonn

%O 1,2

%A _Joseph L. Pe_, May 12 2002

%E a(13)-a(14) from _Vincenzo Librandi_, May 31 2014