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0,3

e^(2/3) = 1.9477340410546758566390...

Table of n, a(n) for n=0..72.

G. Xiao, Contfrac

K. Matthews, Finding the continued fraction of e^(l/m)

If k>0 a(5k)=a(5k+1)=1, a(5k+2)=9k+1, a(5k+3)=36k+18, a(5k+4)=9k+7. - Benoit Cloitre, May 04 2002

ContinuedFraction[ E^(2/3), 100]

Sequence in context: A040311 A221351 A078085 * A097534 A040310 A068610

Adjacent sequences: A069948 A069949 A069950 * A069952 A069953 A069954

nonn,cofr,easy

Elena Andres Sierra (aeroplane27(AT)hotmail.com), Apr 27 2002

Edited and extended by Robert G. Wilson v and Benoit Cloitre, May 04 2002

approved