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A069818
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Let x = 1.757739951145463... be smallest real number that satisfies gcd(floor(x^m),m)=1 for all integers m>0; sequence gives floor(x^n).
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0
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1, 3, 5, 9, 16, 29, 51, 91, 160, 281, 494, 869, 1529, 2687, 4724, 8303, 14595, 25655, 45095, 79267, 139330, 244907, 430483, 756677, 1330042, 2337869, 4109366, 7223197, 12696502, 22317149, 39227744, 68952173, 121199990, 213038065
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OFFSET
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1,2
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COMMENTS
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If some z satisfies the condition gcd(floor(z^n),n)=1, then all positive powers of z also satisfy the condition. There are an infinite number of reals satisfying this condition; the value given here is the smallest such solution.
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LINKS
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FORMULA
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Floor(x^n), x=1.757739951145463 approximately.
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EXAMPLE
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gcd(floor(x^10),10) = gcd(281,10) = 1; the floor of even powers of x is always odd.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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