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A069199
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a(1)=1 a(2)=7 a(n+2)=(a(n+1)+a(n))/3 if (a(n+1)+a(n)==0 (mod 3)); a(n+2)=(a(n+1)+a(n))/2 if (a(n+1)+a(n)==0 (mod 2)); a(n+2)=a(n+1)+a(n) otherwise.
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0
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1, 7, 4, 11, 5, 8, 13, 7, 10, 17, 9, 13, 11, 8, 19, 9, 14, 23, 37, 20, 19, 13, 16, 29, 15, 22, 37, 59, 32, 91, 41, 44, 85, 43, 64, 107, 57, 82, 139, 221, 120, 341, 461, 401, 431, 416, 847, 421, 634, 1055, 563, 809, 686, 1495, 727, 1111, 919, 1015, 967, 991, 979, 985
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,2
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COMMENTS
| A Collatz-Fibonacci mixture. Does this sequence diverge to infinity? Conjecture : if a(1)=1 and a(2)=2 sequence is constant = 1, if a(2)=5 sequence is cyclic = (5,2,7,3) but if a(2)=m, different from 2 or 5, sequence diverges.
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CROSSREFS
| Sequence in context: A195452 A103227 A165415 * A138339 A107827 A070406
Adjacent sequences: A069196 A069197 A069198 * A069200 A069201 A069202
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KEYWORD
| easy,nonn
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AUTHOR
| Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 11 2002
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