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A068633
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a(1) = 11 by convention; for n > 1, if n = p^a*q^b... then a(n) = concatenation paqb...
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2
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11, 21, 31, 22, 51, 2131, 71, 23, 32, 2151, 111, 2231, 131, 2171, 3151, 24, 171, 2132, 191, 2251, 3171, 21111, 231, 2331, 52, 21131, 33, 2271, 291, 213151, 311, 25, 31111, 21171, 5171, 2232, 371, 21191, 31131, 2351, 411, 213171, 431, 22111
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| a(31) = a(177147) = 311. Is there any solution to a(n) = n? - Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), Dec 18 2006
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EXAMPLE
| a(42) = 213171 as 42 = 2^1*3^1*7^1.
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CROSSREFS
| Apart from initial term, a duplicate of A067599.
Sequence in context: A109686 A077522 A049201 * A123849 A108812 A017281
Adjacent sequences: A068630 A068631 A068632 * A068634 A068635 A068636
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KEYWORD
| base,easy,nonn
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AUTHOR
| Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Feb 27 2002
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