OFFSET
1,1
COMMENTS
Sum_{k>=1} 1/(k * 2^k) = log(2).
PROG
(PARI) a(n) = denominator(sum(k=1, n, 1/(k * 2^k))); \\ Michel Marcus, Jun 26 2019
CROSSREFS
KEYWORD
easy,frac,nonn
AUTHOR
Benoit Cloitre, Mar 25 2002
STATUS
approved