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A068508
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a(n)=round[(a(n-1)+a(n-2))/a(n-3)] starting with a(1)=a(2)=a(3)=1.
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2
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1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,4
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COMMENTS
| While this sequence has period 8, the unrounded version b(n)=(b(n-1)+b(n-2))/b(n-3) seems to have a quasi-period of about 8.7 for this particular starting point.
Terms of the simple continued fraction of 1198/[sqrt(5368485)-1563]. [From Paolo P. Lava (paoloplava(AT)gmail.com), Aug 06 2009]
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LINKS
| Index to sequences with linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,1).
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FORMULA
| a(n)=a(n-8)
a(n)=1/56*{19*(n mod 8)+12*[(n+1) mod 8]+12*[(n+2) mod 8]-9*[(n+3) mod 8]-2*[(n+4) mod 8]-2*[(n+5) mod 8]+5*[(n+6) mod 8]+5*[(n+7) mod 8]} with n>=0 - Paolo P. Lava (paoloplava(AT)gmail.com), Nov 27 2006
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EXAMPLE
| a(7)=round[(a(6)+a(5))/a(4)]=round[(5+3)/2]=4
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CROSSREFS
| Cf. A048112.
Sequence in context: A060444 A152814 A021981 * A137403 A082233 A058981
Adjacent sequences: A068505 A068506 A068507 * A068509 A068510 A068511
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KEYWORD
| nonn,easy
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AUTHOR
| Henry Bottomley (se16(AT)btinternet.com), Mar 25 2002
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