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A068342
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a(1) = 1; a(n+1) = (product{k|n} a(k)) (sum{j|n} 1/a(j)), where both the product and sum are over the positive divisors of n.
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0
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1, 1, 2, 3, 7, 8, 42, 43, 304, 914, 13717, 13718, 1948004, 1948005, 165580467, 3808350755, 1157738629649, 1157738629650, 14800530641450464, 14800530641450465, 703750431470328179479, 90080055228202006973396
(list; graph; refs; listen; history; internal format)
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