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A068310 n^2 - 1 divided by its largest square divisor. 9
3, 2, 15, 6, 35, 3, 7, 5, 11, 30, 143, 42, 195, 14, 255, 2, 323, 10, 399, 110, 483, 33, 23, 39, 3, 182, 87, 210, 899, 15, 1023, 17, 1155, 34, 1295, 38, 1443, 95, 1599, 105, 1763, 462, 215, 506, 235, 138, 47, 6, 51, 26, 2703, 78, 2915, 21, 3135, 203, 3363, 870, 3599 (list; graph; refs; listen; history; text; internal format)
OFFSET
2,1
COMMENTS
In other words, squarefree part of n^2-1.
Least m for which x^2 - m*y^2 = 1 has a solution with x = n.
LINKS
FORMULA
a(n) = A007913(n^2-1).
a(n) = A005563(n-1) / A008833(n^2 - 1)). [Reinhard Zumkeller, Nov 26 2011; corrected by Georg Fischer, Dec 10 2022]
EXAMPLE
a(6) = 35, as 6^2 - 1 = 35 itself is squarefree.
7^2-1 = 48 = A005563(6), whose largest square divisor is A008833(48) = 16, so a(7) = 48/16 = 3.
MATHEMATICA
a[n_] := Times@@(#[[1]] ^ Mod[ #[[2]], 2]&/@FactorInteger[n^2-1])
Table[(n^2-1)/Max[Select[Divisors[n^2-1], IntegerQ[Sqrt[#]]&]], {n, 2, 60}] (* Harvey P. Dale, Dec 08 2019 *)
PROG
(PARI) a(n) = core(n*n - 1); \\ David Wasserman, Mar 07 2005
(Haskell)
a068310 n = f 1 $ a027746_row (n^2 - 1) where
f y [] = y
f y [p] = y*p
f y (p:ps'@(p':ps)) | p == p' = f y ps
| otherwise = f (y*p) ps'
-- Reinhard Zumkeller, Nov 26 2011
CROSSREFS
Sequence in context: A328282 A332215 A086485 * A033314 A070260 A142705
KEYWORD
easy,nice,nonn
AUTHOR
Lekraj Beedassy, Feb 25 2002
EXTENSIONS
Edited by Dean Hickerson, Mar 19 2002
Entry revised by N. J. A. Sloane, Apr 27 2007
STATUS
approved

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Last modified April 25 09:25 EDT 2024. Contains 371967 sequences. (Running on oeis4.)