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A068156
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G.f.: (x+2)*(x+1)/((x-1)*(x-2)) = Sum_{n>=0} a(n)*(x/2)^n.
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30
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1, 3, 9, 21, 45, 93, 189, 381, 765, 1533, 3069, 6141, 12285, 24573, 49149, 98301, 196605, 393213, 786429, 1572861, 3145725, 6291453, 12582909, 25165821, 50331645, 100663293, 201326589, 402653181, 805306365, 1610612733
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OFFSET
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0,2
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COMMENTS
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Number of moves to solve Hard Pagoda puzzle.
Partial sums of A111286. Binomial transform of (1,2,4,2,4,2,4 ....). - Paul Barry, Feb 28 2003
Warren W. Kokko writes that this sequence also appears to give the number of scoring sequences for the Racer Dice Game with n dice. - N. J. A. Sloane, Feb 24 2015
For n > 0, a(n) is the number of identical bowls having the same weight except for one which has a higher weight than the others which are identifiable by a weighing machine using n weighings.
Example: a(2)=9 because two weighings are sufficient:
Start with 9 bowls;
Step 1: remove 3 bowls => there are still 6 bowls;
Step 2: first weighing of 6 bowls (3 bowls on each side of the weighing machine);
Step 3: if the machine is in equilibrium, we find immediately the unknown bowl with a second weighing from the first 3 removing bowls. Else, we find immediately the unknown bowl with a second weighing from the 3 heaviest bowls.
Note: If the unknown bowl has a lower weight, the reasoning is the same, but it is necessary to know whether the unknown bowl is heavier or lighter.
In the general case, we always remove 3 bowls in step 1.
(End)
The number of ternary words of length n that avoid {11-2,22-1}. G.f. [1+(k-1)*x^2]/[1-k*x+(k-1)*x^2] at k=3. [Theorem 7.93 by Heubach and Mansour]. - R. J. Mathar, May 22 2016
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REFERENCES
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Richard I. Hess, Compendium of Over 7000 Wire Puzzles, privately printed, 1991.
Richard I. Hess, Analysis of Ring Puzzles, booklet distributed at 13th International Puzzle Party, Amsterdam, Aug 20 1993.
S. Heubach, T. Mansour, in Combinatorics of Compositions and words, Discr. Math. Applicat. (ed by K H Rosen), CRC Press 2010, p 300.
Warren W. Kokko, The Racer Dice Game, Manuscript, 2015.
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LINKS
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FORMULA
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a(0) = 1, a(n) = A060482(2n+1). For n > 0, a(n+1) = 2*a(n)+3.
G.f.: (1+2*x^2)/((1-2*x)*(1-x)). - Paul Barry, Feb 28 2003
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MATHEMATICA
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CoefficientList[Series[(1+2x^2)/((1-2x)(1-x)), {x, 0, 40}], x] (* Harvey P. Dale, Jan 02 2022 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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