%I #27 Feb 10 2019 17:14:24
%S 1,3,5,7,9,111,131,151,171,191,212,232,252,272,292,313,333,353,373,
%T 393,414,434,454,474,494,515,535,555,575,595,616,636,656,676,696,717,
%U 737,757,777,797,818,838,858,878,898,919,939,959,979,999,10101,10301,10501
%N Palindromic numbers j that are not of the form k + reverse(k) for any k.
%C Intersection of A002113 and A067031. Every palindrome with an even number of digits is of the form k + reverse(k), for example 123321 = 123000 + 000321, so the sequence has no terms with an even number of digits.
%C It seems that the terms follow a strict pattern: x1x', x3x', x5x', x7x', x9x', y1y', y3y', y5y', y7y', y9y' and so on. x' is reverse(x). Apart from the first 5 terms in the sequence, the surrounding terms (x and y) simply iterate over the positive integers. - _Dmitry Kamenetsky_, Mar 10 2017
%C Every palindrome with an odd number of digits is of the form k + reverse(k) if the central digit is even, for example 1234321 = 1232000 + 0002321, so no term with an odd number of digits has an even central digit. - _A.H.M. Smeets_, Feb 01 2019
%H Michel Marcus, <a href="/A068061/b068061.txt">Table of n, a(n) for n = 1..500</a>
%e 9 belongs to this sequence, since there is no k such that k + reverse(k) = 9 (cf. A067031).
%o (PARI) isok(n) = {if (Pol(d=digits(n)) == Polrev(d), for (k=1, n-1, if (k + fromdigits(Vecrev(digits(k))) == n, return (0));); 1;);} \\ _Michel Marcus_, Mar 12 2017
%Y Cf. A002113, A067031, A068062.
%K base,easy,nonn
%O 1,2
%A _Klaus Brockhaus_, Feb 15 2002