A067938 Let rep(n) be the n-th repunit number, sequence gives values of n such that rep(n)==rep(5) (mod n).

1, 2, 4, 5, 8, 10, 11, 16, 20, 25, 32, 35, 40, 50, 55, 65, 74, 77, 80, 85, 95, 100, 101, 115, 125, 143, 145, 155, 160, 185, 200, 205, 215, 235, 250, 265, 275, 295, 296, 305, 335, 355, 365, 395, 400, 407, 410, 415, 445, 455, 485, 500, 505, 515, 535, 545, 565, 620