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There are no self-conjugate partitions of 2, so we set a(2)=0.
Table of n, a(n) for n=0..87.
a(n) = r - (s mod 2), where n = r(r+1)/2 + s with 0 <= s <= r; i.e. r = floor((sqrt(8n+1)-1)/2).
r[n_] := Floor[(Sqrt[8n+1]-1)/2]; s[n_] := n-r[n](r[n]+1)/2; a[n_] := r[n]-Mod[s[n], 2]
Cf. A000700, A067694.
Sequence in context: A268835 A006641 A115756 * A147844 A130634 A053735
Adjacent sequences: A067728 A067729 A067730 * A067732 A067733 A067734
Naohiro Nomoto, Feb 05 2002
Edited by Dean Hickerson, Feb 15 2002