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a(n)=(5^n)!/5^(floor(5^n/4)).
0

%I #5 Mar 30 2012 18:38:51

%S 24,992717442773183102976,

%T 40430184518317723114801581310112416990289059355748360594946908815790677863132786902106242711047388589217057430911294714969909793737790976356051669072468180437703895774095957648134608257024

%N a(n)=(5^n)!/5^(floor(5^n/4)).

%C 5^(floor(5^n/4)) is the highest power of 5 dividing (5^n)!

%K nonn,bref

%O 1,1

%A _Benoit Cloitre_, Feb 04 2002