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a(n)=(3^n)!/3^(floor(3^n/2)).
0

%I #5 Mar 30 2012 18:38:51

%S 2,4480,6829776306569216000000,

%T 476828881356392543041592797163461605193984896811956028519492400892855796105719316480000000000000000000

%N a(n)=(3^n)!/3^(floor(3^n/2)).

%C 3^(floor(3^n/2)) is the highest power of 3 dividing (3^n)!

%K nonn

%O 1,1

%A _Benoit Cloitre_, Feb 04 2002