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Number of distinct prime factors in floor((3/2)^n).
0

%I #7 Aug 26 2020 18:15:50

%S 0,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,2,3,1,1,3,3,3,3,3,2,4,4,2,2,2,3,

%T 2,4,5,4,3,4,5,4,4,5,3,2,2,2,4,5,5,4,4,4,3,5,3,2,2,5,3,2,2,3,2,5,2,3,

%U 2,4,4,6,7,6,4,3,4,5,5,6,6,3,2,2,3,4,5,2,2,4,5,6,5,4,2,2,3,1,3,2,5,6,6,5,3

%N Number of distinct prime factors in floor((3/2)^n).

%t PrimeNu[Floor[(3/2)^Range[110]]] (* _Harvey P. Dale_, Aug 26 2020 *)

%K easy,nonn

%O 1,9

%A _Benoit Cloitre_, Feb 23 2002