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%I #6 Dec 29 2018 11:30:24
%S 12,1324,135246,13572468,1357924680,135791246802,13579132468024,
%T 1357913524680246,135791357246802468,13579135792468024680,
%U 1357913579124680246802,135791357913246802468024
%N a(n) = a number with 2n digits with first n digits odd and the rest even, in cyclic increasing order.
%e The sixth term is the concatenation of 135791 and 246802 so a(6)= 135791246802
%t FromDigits/@Table[Join[PadRight[{},n,Range[1,9,2]],PadRight[{},n,{2,4,6,8,0}]],{n,12}] (* _Harvey P. Dale_, Dec 29 2018 *)
%K easy,nonn,base,less
%O 1,1
%A _Amarnath Murthy_, Jan 08 2002
%E More terms from Larry Reeves (larryr(AT)acm.org), Apr 03 2002
%E Edited by _Charles R Greathouse IV_, Apr 24 2010
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