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a(n) = ceiling(10^(n-1)/n).
2

%I #21 Dec 07 2024 18:31:33

%S 1,5,34,250,2000,16667,142858,1250000,11111112,100000000,909090910,

%T 8333333334,76923076924,714285714286,6666666666667,62500000000000,

%U 588235294117648,5555555555555556,52631578947368422,500000000000000000

%N a(n) = ceiling(10^(n-1)/n).

%H Harry J. Smith, <a href="/A066559/b066559.txt">Table of n, a(n) for n = 1..150</a>

%F a(n) = A053041(n)/n.

%p A066559:=n->ceil(10^(n-1)/n); seq(A066559(n), n=1..30); # _Wesley Ivan Hurt_, Nov 28 2013

%t Table[Ceiling[10^(n - 1)/n], {n, 30}] (* _Wesley Ivan Hurt_, Nov 28 2013 *)

%o (PARI) a(n) = { ceil(10^(n-1)/n) } \\ _Harry J. Smith_, Feb 23 2010

%Y Cf. A053041, A066209, A066557, A066558.

%K nonn

%O 1,2

%A _Amarnath Murthy_, Dec 17 2001

%E Corrected, extended by, and better name from _Vladeta Jovovic_, Dec 17 2001