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A066497
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Least number k such that phi(k) / Carmichael lambda(k) = 2n.
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1
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8, 24, 63, 80, 275, 252, 1247, 240, 513, 825, 1541, 455, 4187, 3277, 1891, 1040, 14111, 819, 43739, 2200, 2107, 4623, 6533, 1365, 15251, 8321, 8829, 6235, 13747, 2387, 116003, 2720, 13333, 42333, 14981, 3276, 33227, 131217, 12403, 4400, 61337
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OFFSET
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1,1
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COMMENTS
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Except when Phi(n) = Lambda(n), the value Phi(n)/Lambda(n) must be even.
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LINKS
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MATHEMATICA
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nn = 75; a = Table[0, {nn}]; found = 0; k = 0; While[found < nn, k++; b = EulerPhi[k]/CarmichaelLambda[k]; If[IntegerQ[b/2] && b/2 <= nn && a[[b/2]] == 0, a[[b/2]] = k; found++]]; a
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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