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Position of sqrt(n) in the mapping N2QuQR2 given in A065937.
4

%I #2 May 01 2014 02:49:32

%S 1,25,223,3,3585,14847,30458,8053063679,7,128849018881,31588351,

%T 134140418588671,32178205,129990652,

%U 1318594171818636545920576603798101819391,15

%N Position of sqrt(n) in the mapping N2QuQR2 given in A065937.

%p [seq(QuQR1toQuQR2(frac2position_in_0_1_SB_tree(sqrt_n_confrac2binfrac(n))), n=1..40)];

%Y a[n] = A065934[A065938[n]].

%K nonn

%O 1,2

%A _Antti Karttunen_, Dec 07 2001