A065121 - OEIS

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A065121

Least m such that maximal palindrome in period of continued fraction for sqrt(m) is n-th row of Pascal's triangle; or 0 if no such number exists.

3, 0, 14, 218, 164, 7316138, 42678240 (list; graph; refs; listen; history; internal format)

	OFFSET	`0,1`
	COMMENTS	`A056825 is a similar sequence based on the same maximal palindrome.`
	EXAMPLE	`For n=3, continued fraction for sqrt(218) is [[14],[1,3,3,1,28]]. Maximal palindrome in period -> (1,3,3,1) is the 3rd row of Pascal's triangle.`
	CROSSREFS	`Cf. A003285.` `Sequence in context: A008403 A138349 A135399 * A167339 A138540 A123023` `Adjacent sequences: A065118 A065119 A065120 * A065122 A065123 A065124`
	KEYWORD	`fini,nonn`
	AUTHOR	`Naohiro Nomoto (n_nomoto(AT)yabumi.com), Nov 13 2001`

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Last modified February 14 18:09 EST 2012. Contains 205663 sequences.