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%I #6 Apr 09 2014 10:16:29
%S 1,1,2,5,31,1231,1917121,4667676800641,27640053867460068128570881,
%T 969475805641849161579046591814284573846079748476161
%N Let r_1 = 1; r_{n+1} = [r_1; r_2, r_3,..., r_n]; n-th term is numerator of r_n.
%C [r_1; r_2, r_3,..., r_n] is a continued fraction, where the r's are rationals. limit{n -> infinity} r_n = 1.7118691868...
%Y Cf. A053978, A064846.
%K easy,frac,nonn
%O 1,3
%A _Leroy Quet_, Oct 31 2001