%I #1 May 16 2003 03:00:00
%S 1,2,3,4,5,6,7,8,9,10,11,13,14,15,17,18,19,20,21,22,23,26,27,28,29,30,
%T 31,33,34,35,37,38,39,40,41,42,43,44,45,46,47,49,50,51,53,54,55,57,58,
%U 59,60,61,62,63,65,66,67,68,69,70,71,73,74,77,78,79,80,81,82,83,84,85
%N Let n(s) be the number formed from n by inserting s 0's between each digit, e.g. 123(2) is 1002003; sequence gives numbers n such that n(s) is divisible by n for some s>0.
%C If n=d(v)*10^v + d(v-1)*10^(v-1) .. + d(1)*10+d(0) then n(s) = d(v)*10^(v*(1+s))+d(v-1)*10^(v-1)*(1+s)+ .. + d(1)*10^(1+s)+d(0); e.g. 123(2) is 1*10^(2*3)+ 2*10^(1*3)+3*10^(0*3) = 1002003.
%e a(12) = 13 because 13(6) = 10,000,003 which is divisible by 13
%Y Cf. A064695, A064696, A064697, A064698.
%K base,nonn
%O 1,2
%A Jonathan Ayres (jonathan.ayres(AT)btinternet.com), Oct 10 2001