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A064025 Length of period of the continued fraction for sqrt(n!). 2
1, 2, 2, 2, 4, 2, 16, 48, 8, 4, 56, 180, 44, 156, 300, 7936, 10388, 11516, 9104, 13469268, 2684084, 2418800, 28468692, 143007944, 85509116, 402570696, 2287868888, 204306960, 48715166536, 147160740856, 317585614148 (list; graph; refs; listen; history; text; internal format)
OFFSET
2,2
LINKS
FORMULA
a(n) = A003285(A000142(n)). - Michel Marcus, Sep 25 2019
EXAMPLE
Quotients for 10! are [[1904], [1, 15, 1, 13, 1, 15, 1, 3808]], so period length of 10! is 8.
MAPLE
with(numtheory): [seq(nops(cfrac(sqrt(k!), 'periodic', 'quotients')[2]), k=2..16)];
MATHEMATICA
Do[ Print[ Length[ Last[ ContinuedFraction[ Sqrt[ n! ]]]]], {n, 2, 24} ]
CROSSREFS
Sequence in context: A216951 A366628 A320305 * A182154 A273875 A054709
KEYWORD
nonn,more
AUTHOR
Labos Elemer, Sep 18 2001
EXTENSIONS
More terms from Robert G. Wilson v, Oct 01 2001
a(25)-a(28) from Daniel Suteu, Jan 24 2019
a(29) from Chai Wah Wu, Sep 23 2019
a(30) from Chai Wah Wu, Sep 25 2019
a(31) from Chai Wah Wu, Jan 27 2021
a(32) from Chai Wah Wu, Feb 02 2021
STATUS
approved

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Last modified March 18 22:56 EDT 2024. Contains 370952 sequences. (Running on oeis4.)