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A063647 Number of ways to write 1/n as a difference of exactly 2 unit fractions. 19
0, 1, 1, 2, 1, 4, 1, 3, 2, 4, 1, 7, 1, 4, 4, 4, 1, 7, 1, 7, 4, 4, 1, 10, 2, 4, 3, 7, 1, 13, 1, 5, 4, 4, 4, 12, 1, 4, 4, 10, 1, 13, 1, 7, 7, 4, 1, 13, 2, 7, 4, 7, 1, 10, 4, 10, 4, 4, 1, 22, 1, 4, 7, 6, 4, 13, 1, 7, 4, 13, 1, 17, 1, 4, 7, 7, 4, 13, 1, 13, 4, 4, 1, 22, 4, 4, 4, 10, 1, 22, 4, 7, 4, 4, 4 (list; graph; refs; listen; history; internal format)
OFFSET

1,4

COMMENTS

If 1/n=1/b-1/c then n=bc/(c-b) and 1/n=1/(2n-b)+1/(c+2n) (though it is also the case that 1/n=1/(2n)+1/(2n) equivalent to b=c=0).

Also number of divisors of n^2 less than n. - Vladeta Jovovic (vladeta(AT)eunet.rs), Aug 13 2001

Also number of decompositions of divisors of n into coprime pairs. - K.B. Subramaniam (kb_subramaniambalu(AT)yahoo.com) and Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Dec 24 2001

Number of elements in the set {(x,y): x|n, y|n, x<y, GCD(x,y)=1}. - Vladeta Jovovic (vladeta(AT)eunet.rs), May 03 2002

Also number of positive integers of the form k*n/(k+n). - Benoit Cloitre (benoit7848c(AT)orange.fr), Jan 04 2002

This is similar to A062799, having the same first 29 terms. But they are different sequence.

If A001221(n)<=2, then a(n)=A062799(n); if A001221(n)>2, then a(n)>A062799(n). A001221(n), or omega(n), is the number of distinct primes dividing n. - Matthew Vandermast (ghodges14(AT)comcast.net), Aug 25 2004

REFERENCES

Problem 1051(b), American Mathematical Monthly, Vol. 105, No. 4, 1998 p. 372.

Amarnath Murthy, Decomposition of The divisors of a natural number into pairwise coprime sets, Smarandache Notions Journal, vol. 12, No. 1-2-3, Spring 2001. pp. 303-306.

LINKS

T. D. Noe, Table of n, a(n) for n=1..10000

Canadian Math. Soc., "Crux Mathematicorum", Vol. 23, No. 7 (Nov 1997), pp 443-4 Soln. to Prob. 2175

FORMULA

a(n) = (tau(n^2)-1)/2.

a(n) = A018892(n)-1. If n = (p1^a1)(p2^a2)...(pt^at), a(n) = ((2*a1+1)(2*a2+1)...(2*at+1)-1)/2.

If n is prime a(n)=1. Conjecture: (1/n)*sum(i=1, n, a(i))=C*ln(n)*ln(ln(n))+o(ln(n)) with C=0.7...

Bisection of A046079. - Lekraj Beedassy (blekraj(AT)yahoo.com), Jul 09 2004

EXAMPLE

a(10) = 4 since 1/10 = 1/5-1/10 = 1/6-1/15 = 1/8-1/40 = 1/9-1/90.

a(12) = 7: the divisors of 12 are 1, 2, 3, 4, 6 and 12 and the decompositions are (1, 2), (1, 3), (1, 4), (1, 6), (1, 12), (2, 3), (3, 4).

MATHEMATICA

Table[(Length[Divisors[n^2]] - 1)/2, {n, 1, 100}]

PROG

(PARI) for(n=1, 100, print1(sum(i=1, n^2, if((n*i)%(i+n), 0, 1)), ", "))

CROSSREFS

Cf. A018892, A063427, A063428. First twenty-nine terms identical to those of A062799 (offset).

Cf. A063717, A063718, A048691.

Sequence in context: A067614 A113901 A062799 * A077808 A021471 A088372

Adjacent sequences:  A063644 A063645 A063646 * A063648 A063649 A063650

KEYWORD

nonn,easy,nice

AUTHOR

Henry Bottomley (se16(AT)btinternet.com), Jul 23 2001

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Last modified February 17 02:48 EST 2012. Contains 205978 sequences.