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Number k such that omega(k) = omega(k+3), where omega(k) is the number of distinct prime divisors of k.
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%I #16 Jun 26 2018 13:03:20

%S 2,4,5,8,12,13,15,16,18,21,29,33,35,36,45,48,51,52,54,55,61,62,64,65,

%T 69,72,74,77,82,85,88,91,92,93,95,96,102,108,112,115,116,119,125,128,

%U 133,141,142,143,144,145,152,155,158,159,161,165,172,175,184,185,189

%N Number k such that omega(k) = omega(k+3), where omega(k) is the number of distinct prime divisors of k.

%H Harry J. Smith, <a href="/A063465/b063465.txt">Table of n, a(n) for n = 1..1000</a>

%o (PARI) select(m->omega(m) == omega(m + 3), [1..350])

%K nonn

%O 1,1

%A _Jason Earls_, Jul 26 2001