%I #5 Mar 30 2012 17:27:33
%S 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,
%T 1,1,1,1,1,1,1,1,1,1,1,1,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,1,1,1,1,1,2,1,
%U 2,1,2,1,1,2,1,2,1,2,1,1,1,1,0,1,2,2,2,2,2,2,2,1,1,1,1
%N Number of 'Reverse and Add!' operations that have to be applied to the n-th term of A063434 in order to obtain a term in the trajectory of 10577.
%H <a href="/index/Res#RAA">Index entries for sequences related to Reverse and Add!</a>
%e 12557 is a term of A063434. One 'Reverse and Add!' operation applied to 12557 leads to a term (88078) in the trajectory of 10577, so the corresponding term of the present sequence is 1.
%Y A023108, A033865, A063433, A063434.
%K base,nonn
%O 0,48
%A _Klaus Brockhaus_, Jul 20 2001