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%I #5 Mar 30 2012 17:27:33
%S 1,1,1,1,1,1,1,1,1,1,1,3,1,3,1,1,1,1,1,1,1,1,1,1,1,3,1,3,1,1,1,1,1,1,
%T 1,1,1,1,1,1,3,1,3,1,1,1,1,1,1,1,1,1,1,0,1,3,1,3,1,1,1,1,1,3,1,3,1,1,
%U 1,1,1,3,1,3,1,1,1,1,1,3,1,3,1,1,1,1,1,1,1,1,1,1,2,1,2,1,2,3,1,2,3,1,1,1,0
%N a(n) = number of 'Reverse and Add!' operations that have to be applied to the n-th term of A063064 in order to obtain a term in the trajectory of 10563.
%H <a href="/index/Res#RAA">Index entries for sequences related to Reverse and Add!</a>
%e 12543 is a term of A063064. One 'Reverse and Add!' operation applied to 12543 leads to a term (47064) in the trajectory of 10563, so the corresponding term of the present sequence is 1.
%Y A023108, A033865, A063063, A063064.
%K base,nonn
%O 0,12
%A _Klaus Brockhaus_, Jul 07 2001
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