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A062866
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Triangle of number of permutations by barycenter.
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10
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1, 1, 2, 1, 4, 1, 1, 4, 14, 4, 1, 1, 5, 31, 46, 31, 5, 1, 1, 6, 66, 146, 282, 146, 66, 6, 1, 1, 7, 134, 392, 1289, 1394, 1289, 392, 134, 7, 1, 1, 8, 267, 960, 4859, 7736, 12658, 7736, 4859, 960, 267, 8, 1, 1, 9, 529, 2235, 16615, 34659, 85831, 83122, 85831, 34659, 16615, 2235, 529, 9, 1
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OFFSET
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0,3
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COMMENTS
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The barycenter or signcenter of a permutation is the sum of the signs of the difference between initial and final positions of the objects.
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LINKS
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FORMULA
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T(n,k) = T(n,-k).
Sum_{k>=0} T(n,k) = A179566(n). (End)
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EXAMPLE
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(1,3,2,5,7,6,4) has difference (0,1,-1,1,2,0,-3) and signs (0,1,-1,1,1,0,-1) with total 1. This is one of 1289 such permutations of degree 7.
Triangle begins:
: 1 ;
: 1 ;
: 2 ;
: 1, 4, 1 ;
: 1, 4, 14, 4, 1 ;
: 1, 5, 31, 46, 31, 5, 1 ;
: 1, 6, 66, 146, 282, 146, 66, 6, 1 ;
: 1, 7, 134, 392, 1289, 1394, 1289, 392, 134, 7, 1 ;
: 1, 8, 267, 960, 4859, 7736, 12658, 7736, 4859, 960, 267, 8, 1 ;
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MAPLE
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b:= proc(s, t) option remember; (n-> `if`(n=0, x^t,
add(b(s minus {j}, t+signum(n-j)), j=s)))(nops(s))
end:
T:= n-> (p-> seq(coeff(p, x, i), i=ldegree(p)..degree(p)))(b({$1..n}, 0)):
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MATHEMATICA
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row[n_] := Sort[Tally[Total[Sign[# - Range[n]]]& /@ Permutations[Range[n]] ]][[All, 2]]; Array[row, 9] // Flatten (* Jean-François Alcover, Oct 07 2016 *)
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CROSSREFS
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KEYWORD
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nice,nonn,tabf
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AUTHOR
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STATUS
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approved
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