OFFSET
1,6
FORMULA
Note that a(k^2)=0 or 1 since each prime can be written only in one way as a difference of squares: (n+b)^2-n^2=p where p is a prime, only if b^2+2nb=b(b+2n) is prime, only if b=1. In that case p=2n+1; since every prime is an odd number we get an 1 in the distribution of a(k^2) for each odd number which is prime.
MATHEMATICA
a[n_] := Length[Select[n-Range[1, Floor[Sqrt[n]]]^2, #==1||PrimeQ[ # ]&]]
CROSSREFS
KEYWORD
nonn
AUTHOR
Santi Spadaro, Jul 20 2001
EXTENSIONS
Corrected and extended by Dean Hickerson, Jul 26, 2001
STATUS
approved