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A062804
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phi(n) - floor(n^(1/3))*tau(n) = 0.
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0
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1, 3, 9, 15, 56, 102, 198, 228, 234, 280, 312, 528, 672, 756, 1050, 1320
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OFFSET
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1,2
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COMMENTS
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LINKS
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EXAMPLE
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For m=1320, Phi[m]-k[m]*Tau[m]=320-10*32=0. 16 terms below 100000 [and most likely at all]. phi(n)-Floor[n^(1/3)]*Tau[n] becomes positive for large n. At n=2520 seems last time negative.
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MATHEMATICA
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Flatten[Position[Table[EulerPhi[w]-Floor[w^(1/3)//N]*DivisorSigma[0, w], {w, 1, 100000}], 0]]
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PROG
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(PARI) isok(n) = eulerphi(n) - sqrtnint(n, 3)*numdiv(n) == 0; \\ Michel Marcus, Aug 24 2019
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CROSSREFS
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KEYWORD
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fini,nonn
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AUTHOR
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STATUS
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approved
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