%I
%S 1,2,1,3,1,1,4,2,0,1,5,2,2,1,1,6,3,0,3,2,1,7,3,3,3,5,3,1,8,4,0,
%T 6,8,8,4,1,9,4,4,6,14,16,12,5,1,10,5,0,10,20,30,28,17,6,1,11,5,5,
%U 10,30,50,58,45,23,7,1,12,6,0,15,40,80,108,103,68,30,8,1,13,6,6,15,55,120,188,211,171,98,38,9,1,14,7,0,21,70,175
%N Table by antidiagonals of coefficient of x^k in expansion of 1/((1+x)^2*(1x)^n).
%F Each row is partial sum of preceding row, i.e. T(n, k)=T(n1, k)+T(n, k1) with T(0, k)=(k+1)*(1)^k and T(n, 0)=1.
%Y Rows are effectively (with minor adjustments): A038608, A001057, A027656, A008805, A006918, A002624, A028346. Cf. A058394 which (adjusting for signs and an overlap of three rows) is effectively the continuation of this table for negative n.
%K sign,tabl
%O 0,2
%A _Henry Bottomley_, Jun 25 2001
