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A062389
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a(n) = floor( (2n-1)*Pi/2 ).
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10
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1, 4, 7, 10, 14, 17, 20, 23, 26, 29, 32, 36, 39, 42, 45, 48, 51, 54, 58, 61, 64, 67, 70, 73, 76, 80, 83, 86, 89, 92, 95, 98, 102, 105, 108, 111, 114, 117, 120, 124, 127, 130, 133, 136, 139, 142, 146, 149, 152, 155, 158, 161, 164, 168, 171, 174, 177, 180, 183, 186
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history;
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OFFSET
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1,2
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COMMENTS
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In general, the complement of a nonhomogenous Beatty sequence [n*r + h] is given by [n*s + h - h*s], where s = r/(r - 1). As an example, the complement of this sequence is A246046. This sequence gives the positive integers k satisfying tan(k) > tan(k + 1), and A246046 gives those satisfying tan(k) < tan(k + 1). - Clark Kimberling, Aug 24 2014
Excluding a(1), a(n) = positive floored solutions to tan(x) = x. - Derek Orr, May 30 2015
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REFERENCES
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M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards Applied Math. Series 55, 1964 (and various reprintings), p. 223.
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LINKS
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M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 [alternative scanned copy].
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MAPLE
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seq(floor((2*n-1)*Pi/2), n=1..1000); # Robert Israel, Jun 01 2015
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MATHEMATICA
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r = Pi; s = Pi/(Pi - 1); h = -Pi/2; z = 120;
u = Table[Floor[n*r + h], {n, 1, z}] (* A062389 *)
v = Table[Floor[n*s + h - h*s], {n, 1, z}] (* A246046 *)
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PROG
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(PARI) j=[]; for(n=1, 150, j=concat(j, floor(1/2*(2*n-1)*Pi))); j
(PARI) { default(realprecision, 50); for (n=1, 1000, write("b062389.txt", n, " ", (2*n - 1)*Pi\2); ) } \\ Harry J. Smith, Aug 06 2009
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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