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Square array read by descending antidiagonals: T(n,k) = floor(n^k/k^n).
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%I #14 May 06 2024 10:12:42

%S 1,0,2,0,1,3,0,0,1,4,0,1,1,1,5,0,1,1,0,0,6,0,1,1,1,0,0,7,0,2,3,1,0,0,

%T 0,8,0,4,6,3,1,0,0,0,9,0,6,12,6,2,0,0,0,0,10,0,10,27,16,4,1,0,0,0,0,

%U 11,0,16,59,39,11,2,0,0,0,0,0,12,0,28,133,104,33,6,1,0,0,0,0,0,13

%N Square array read by descending antidiagonals: T(n,k) = floor(n^k/k^n).

%H Paolo Xausa, <a href="/A062283/b062283.txt">Table of n, a(n) for n = 1..11325</a> (first 150 antidiagonals).

%e T(3,2) = floor(3^2/2^3) = floor(9/8) = 1.

%t Table[Floor[k^(n-k+1)/(n-k+1)^k], {n, 15}, {k, n}] (* _Paolo Xausa_, May 06 2024 *)

%Y Cf. A055651, A060505.

%K nonn,tabl

%O 1,3

%A _Henry Bottomley_, Jul 02 2001