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%I #20 Oct 31 2019 01:23:54
%S 3,17,77,143,149,513,1079,1415,6249,13265,14579,15293,41657,72941
%N Numbers k such that the smoothly undulating palindromic number (75*10^k - 57)/99 is a prime.
%C Prime versus probable prime status and proofs are given in the author's table.
%C No further terms < 100000. - _Ray Chandler_, Aug 17 2011
%H Patrick De Geest, <a href="http://www.worldofnumbers.com/undulat.htm#supp757">SUPP Reference Table - 757</a>
%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>
%e k=17 -> (75*10^17 - 57)/99 = 75757575757575757.
%Y Cf. A062209-A062232, A059758, A032758.
%K nonn,base,more
%O 1,1
%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001
%E a(13)=41657 from _Ray Chandler_, Nov 11 2010
%E a(14)=72941 from _Ray Chandler_, Mar 24 2011
%E Edited by _Ray Chandler_, Aug 17 2011
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