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Numbers k such that the smoothly undulating palindromic number (35*10^k - 53)/99 is a prime.
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%I #15 Aug 11 2024 14:41:34

%S 3,5,23,2177,3147,4157,22713,28385

%N Numbers k such that the smoothly undulating palindromic number (35*10^k - 53)/99 is a prime.

%C Prime versus probable prime status and proofs are given in the author's table.

%C No further terms < 100000. - _Ray Chandler_, Aug 17 2011

%H P. De Geest, <a href="https://www.worldofnumbers.com/undulat.htm#supp353">SUPP Reference Table - 353</a>

%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>

%e k=23 -> (35*10^23 - 53)/99 = 35353535353535353535353.

%Y Cf. A062209-A062232, A059758, A032758.

%K nonn,base

%O 1,1

%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001

%E Edited by _Ray Chandler_, Aug 17 2011