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A062210 Numbers k such that the smoothly undulating number (14*10^k - 41)/99 is a prime. 1
11, 277, 479, 583, 1631, 6343, 14689 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

Prime versus probable prime status and proofs are given in the author's table.

No further terms < 100000. - Ray Chandler, Aug 17 2011

LINKS

Table of n, a(n) for n=1..7.

P. De Geest, SUPP Reference Table - 141

Index entries for sequences related to smoothly undulating palindromic primes

EXAMPLE

11 is in the sequence because (14*10^11 - 41)/99 = 14141414141 is prime.

CROSSREFS

Cf. A062209-A062232, A059758, A032758.

Sequence in context: A108519 A160195 A203240 * A049080 A210807 A129754

Adjacent sequences:  A062207 A062208 A062209 * A062211 A062212 A062213

KEYWORD

nonn,base,more

AUTHOR

Patrick De Geest and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001

EXTENSIONS

Edited by Ray Chandler, Aug 17 2011

Name and Example edited by Jon E. Schoenfield, Jun 25 2017

STATUS

approved

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Last modified September 23 21:16 EDT 2017. Contains 292391 sequences.