

A062210


Numbers k such that the smoothly undulating number (14*10^k  41)/99 is a prime.


1




OFFSET

1,1


COMMENTS

Prime versus probable prime status and proofs are given in the author's table.
No further terms < 100000.  Ray Chandler, Aug 17 2011


LINKS

Table of n, a(n) for n=1..7.
P. De Geest, SUPP Reference Table  141
Index entries for sequences related to smoothly undulating palindromic primes


EXAMPLE

11 is in the sequence because (14*10^11  41)/99 = 14141414141 is prime.


CROSSREFS

Cf. A062209A062232, A059758, A032758.
Sequence in context: A108519 A160195 A203240 * A049080 A210807 A129754
Adjacent sequences: A062207 A062208 A062209 * A062211 A062212 A062213


KEYWORD

nonn,base,more


AUTHOR

Patrick De Geest and Hans Rosenthal (Hans.Rosenthal(AT)tonline.de), Jun 15 2001


EXTENSIONS

Edited by Ray Chandler, Aug 17 2011
Name and Example edited by Jon E. Schoenfield, Jun 25 2017


STATUS

approved



