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FORMULA
| a(n)= (n+5)!*binomial(n+8, 8)/5!; e.g.f.: N(3;5, x)/(1-x)^14 with N(3;5, x) := sum(A062145(5, k)*x^k, k=0..5)= 1+40*x+280*x^2+560*x^3+350*x^4+56*x^5.
If we define f(n,i,x)= sum(sum(binomial(k,j)*stirling1(n,k)*stirling2(j,i)*x^(k-j),j=i..k),k=i..n) then a(n-5)=(-1)^(n-1)*f(n,5,-9), (n>=5). [From Milan R. Janjic (agnus(AT)blic.net), Mar 01 2009]
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