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A062050
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n-th chunk consists of the numbers 1, ..., 2^n.
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20
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1, 1, 2, 1, 2, 3, 4, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17
(list;
graph;
refs;
listen;
history;
text;
internal format)
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OFFSET
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1,3
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COMMENTS
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a(k) is the distance between k and the largest power of 2 not exceeding k, where k = n + 1. [Consider the sequence of even numbers <= k; after sending the first term to the last position delete all odd-indexed terms; the final term that remains after iterating the process is the a(k)-th even number.] - Lekraj Beedassy, May 26 2005
Triangle read by rows in which row n lists the first 2^(n-1) positive integers, n >= 1; see the example. - Omar E. Pol, Sep 10 2013
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LINKS
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FORMULA
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a(n) = n - msb(n) + 1 (where msb(n) = A053644(n)).
a(n) = 1 + n - 2^floor(log(n)/log(2)). - Benoit Cloitre, Feb 06 2003; corrected by Joseph Biberstine (jrbibers(AT)indiana.edu), Nov 25 2008
G.f.: 1/(1-x) * ((1-x+x^2)/(1-x) - Sum_{k>=1} 2^(k-1)*x^(2^k)). - Ralf Stephan, Apr 18 2003
a(1) = 1, a(2*n) = 2*a(n) - 1, a(2*n+1) = 2*a(n). - Ralf Stephan, Oct 06 2003
a(n) = if n < 2 then n else 2*a(floor(n/2)) - 1 + n mod 2. - Reinhard Zumkeller, May 07 2012
Without the constant 1, Ralf Stephan's g.f. becomes A(x) = x/(1-x)^2 - (1/(1-x)) * Sum_{k>=1} 2^(k-1)*x^(2^k)) and satisfies the functional equation A(x) - 2*(1+x)*A(x^2) = x*(1 - x - x^2)/(1 - x^2). - Petros Hadjicostas, Apr 27 2020
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EXAMPLE
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Written as irregular triangle with row lengths A000079:
1;
1, 2;
1, 2, 3, 4;
1, 2, 3, 4, 5, 6, 7, 8;
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16;
...
(End)
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MAPLE
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A062050 := proc(n) option remember; if n < 4 then return [1, 1, 2][n] fi;
2*A062050(floor(n/2)) + irem(n, 2) - 1 end:
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MATHEMATICA
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Flatten[Table[Range[2^n], {n, 0, 6}]] (* Harvey P. Dale, Oct 12 2015 *)
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PROG
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(PARI) a(n)=floor(n+1-2^floor(log(n+1-10^-27)/log(2)))
(Haskell)
a062050 n = if n < 2 then n else 2 * a062050 n' + m - 1
where (n', m) = divMod n 2
(Python)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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