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A061515
a(0) = 1; a(n) is obtained by incrementing each digit of a(n-1) by 3.
0
1, 4, 7, 10, 43, 76, 109, 4312, 7645, 10978, 43121011, 76454344, 109787677, 431210111091010, 7645434443124343, 10978767776457676, 43121011109101010978109109, 76454344431243434312101143124312, 109787677764576767645434476457645, 431210111091010109781091091097876771097810978
OFFSET
0,2
COMMENTS
In A061511-A061522, A061746-A061750 when the incremented digit exceeds 9 it is written as a 2-digit string. So 9+1 becomes the 2-digit string 10, etc.
PROG
(Python)
from itertools import accumulate, repeat
def f(n, _): return int("".join(str(int(d)+3) for d in str(n)))
def aupton(nn): return list(accumulate(repeat(1, nn+1), f))
print(aupton(19)) # Michael S. Branicky, Mar 19 2022
CROSSREFS
Sequence in context: A088405 A100591 A135262 * A071084 A175833 A171964
KEYWORD
base,nonn
AUTHOR
Amarnath Murthy, May 08 2001
EXTENSIONS
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
a(17) corrected and a(18), a(19) by Georg Fischer, Mar 19 2022
STATUS
approved