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%I #9 Nov 09 2019 15:38:08
%S 1,12,123,120304,102030405,10203040506,1020304050607,102030405060708,
%T 10203040506070809,10203040506070809010,10203040506070809010011,
%U 102030405060708009010011012,1020304050607008009010011012013,1020304050607008009010011012013014
%N a(n) = A053062(n) / n.
%H Andrew Howroyd, <a href="/A061088/b061088.txt">Table of n, a(n) for n = 1..100</a>
%e a(5) = 102030405 = 510152025/5, where 510152025 is obtained by concatenating 5,10,15,20 and finally 25 (which is 5^2).
%o (PARI) a(n)={fromdigits(concat(vector(n, k, digits(k*n))))/n} \\ _Andrew Howroyd_, Nov 09 2019
%Y Cf. A053062.
%K nonn,base
%O 1,2
%A _Amarnath Murthy_, Apr 19 2001
%E Offset corrected and terms a(7) and beyond from _Andrew Howroyd_, Nov 09 2019
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